A guy attachment is located 28.5 feet above the ground. The anchor rod is 26 feet from the pole. The guy steel should be cut ? long.

A guy attachment is located 28.5 feet above the ground. The anchor rod is 26 feet from the pole. The guy steel should be cut ? long.

• A. 41.5'
• B. 45.5'
• C. 47.6'
• D. 49.5'

Answer: (A)

The main idea is using the Pythagorean theorem to find the length of the guy wire. The guy forms the hypotenuse of a right triangle where the vertical leg is the attachment height above the ground (28.5 ft) and the horizontal leg is the distance from the pole to the anchor (26 ft). So the length is the square root of the sum of squares: sqrt(28.5^2 + 26^2) = sqrt(812.25 + 676) = sqrt(1488.25) ≈ 38.6 ft. The option given corresponds to a longer length, which would occur if the horizontal distance were about 30 ft (sqrt(28.5^2 + 30^2) ≈ 41.4). This suggests the problem as written may have a mismatch or the solution uses an adjustment for tensioning. The key concept stays: length equals the hypotenuse calculated by the Pythagorean theorem.

The main idea is using the Pythagorean theorem to find the length of the guy wire. The guy forms the hypotenuse of a right triangle where the vertical leg is the attachment height above the ground (28.5 ft) and the horizontal leg is the distance from the pole to the anchor (26 ft). So the length is the square root of the sum of squares: sqrt(28.5^2 + 26^2) = sqrt(812.25 + 676) = sqrt(1488.25) ≈ 38.6 ft. The option given corresponds to a longer length, which would occur if the horizontal distance were about 30 ft (sqrt(28.5^2 + 30^2) ≈ 41.4). This suggests the problem as written may have a mismatch or the solution uses an adjustment for tensioning. The key concept stays: length equals the hypotenuse calculated by the Pythagorean theorem.